Saturday, March 11, 2006

inverse z transform

syms z n;
fz = 5+2*z^(-1)+4*z^(-3);
iztrans(fz)


/>ans =
/>5*charfcn[0](n)+2*charfcn[1](n)+4*charfcn[3](n)

where charfcn[1](n) is the delta function: [tex]\delta[n-1] [/tex]

2 comments:

  1. Sir, what's difference between charfcn[0](n) and charfcn[3](n)?

    I knew that charfcn[0](n) equals to delta nol (n)

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  2. For more MATLAB code and and project visit

    deepeshrawat987.blogspot.com

    ReplyDelete