syms z n;where charfcn[1](n) is the delta function: [tex]\delta[n-1] [/tex]
fz = 5+2*z^(-1)+4*z^(-3);
iztrans(fz)
/>ans =
/>5*charfcn[0](n)+2*charfcn[1](n)+4*charfcn[3](n)
Saturday, March 11, 2006
inverse z transform
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Sir, what's difference between charfcn[0](n) and charfcn[3](n)?
ReplyDeleteI knew that charfcn[0](n) equals to delta nol (n)
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